Math, asked by khatijaamna35, 1 year ago

Find x and y from the following frequency distribution
Classes frequency cf
0-8 15 15
8-16 x 28
16-24 15 43
24-32 18 y
32-40 9 70

Answers

Answered by harsh127715
12
15+x=28
X=28-15
X=13.

Y=43+18
Y=61.

Hope it will help i
Answered by gayatrikumari99sl
1

Answer:

13 and 61 is the required value of x and y .

Step-by-step explanation:

Explanation:

Given , class intervale :0-8, 8-16,16-24 ,24-32,32-40

Frequency : 15, x ,15 , 8 , 9

c.f = 15 , 28 , 43 ,y ,70  ..........(i)

But we know , Cumulative frequency (c.f) can be calculated by adding the frequency of the class interval to the frequency of the second class interval . after that , the sumis added to the frequency of the third class interval and etc.

Step1:

Therefore find out the c.f first then ,

c.f : 15 , 15+x, 30+x, 48+x, y+9 .......(ii)

Now compare (i ) and (ii)

15 = 15

15+x= 28 ⇒x = 28-15 = 13

30+x= 43 ⇒x = 43-30 = 13

48+x = y .......(iii)

now put the value of x = 13 in equation (iii) we get

48+13 = y ⇒y = 61

Final answer :

Hence , the value of x is 13 and y is 61

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