Find x and y if px+qy=p-q and qx-py=p+q by elimination method
Answers
Answered by
1
we have
p x +q y = p -q -(1) and q x - p y = p+ q -(2)
Multiply equation 1 by p and 2 by q
We get ,
p^2(x) + pq (y) = p^2- q p and
q^2(x) - pq(y) = qp + q^2
On addition , we get
(p^2 + q^2) x = p^2 + q^2
OR x = 1
Now , qy = p-p-q
y = -q/q
y =-1
Thus , value of x and y are 1 and -1 respectively
p x +q y = p -q -(1) and q x - p y = p+ q -(2)
Multiply equation 1 by p and 2 by q
We get ,
p^2(x) + pq (y) = p^2- q p and
q^2(x) - pq(y) = qp + q^2
On addition , we get
(p^2 + q^2) x = p^2 + q^2
OR x = 1
Now , qy = p-p-q
y = -q/q
y =-1
Thus , value of x and y are 1 and -1 respectively
Similar questions