Question

find x and y,if
$\frac{ \sqrt{3 - 1} }{ \sqrt{3 + 1} } = x + y \sqrt{3}$
​

Answer 1

Answer:

iska answer aata h ....but mai nhi btaungi

Answer 2

3+1

3−1

=x+y

3

view step

213

\frac{\sqrt{2}}{\sqrt{3+1}}=x+y\sqrt{3}

3+1

2

=x+y

3

view step

431

\frac{\sqrt{2}}{\sqrt{4}}=x+y\sqrt{3}

4

2

=x+y

3

view step

42

\frac{\sqrt{2}}{2}=x+y\sqrt{3}

2

2

=x+y

3

view step

x+y\sqrt{3}=\frac{\sqrt{2}}{2}

x+y

3

=

2

2

view step

y\sqrt{3}

x=\frac{\sqrt{2}}{2}-y\sqrt{3}

x=

2

2

−y

3

view step

x=-\sqrt{3}y+\frac{\sqrt{2}}{2}

x=−

3

y+

2

2

is true