Question

FIND X AND Y IN 11gmPQRS
PLEASE ANSWER FAST​

Answer 1

Step-by-step explanation:

In triangle PSQ, apply angle sum property of triangle,

70 + 40 + PSQ = 180

PSQ = 180 - 110

PSQ = 70

PQRS is Parallelogram

So PS parallel QR and SQ is transversal

PSQ = RQS = 70

PQRS is Parallelogram

So SR parallel PQ and SQ is transversal so,

y = 40 ( alternate angles property)

Now apply angle sum property in triangle QSR

y + x + RSQ = 180

40 + x + 70 = 180

x = 180 - 110

x = 70

Answer 2

y ==40 ( alternative angel) •.• SR || PQ

∆ PQS me

70+40+ angel PSQ=180

angle PSQ = 180 -110

angle PSQ = 70

NOW

∆ SQR ME

40 +70+X = 180

X = 180-110

X= 70

THE VALUE OF

X ==== 70

AND VALUE OF

Y====40

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