find x and y in the figure
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Taking the triangle BCM
Using the Pythagorean’s theorem, we get
20^2 = 16^2 + 12^2
400 = 256 + 144
Likewise take the two triangles;
CBA & CMA
(16+y)^2 = 20^2 +x^2—-(1)
X^2 =12^2 + y^2——-(2)
So substitute the value of x^2 in (1)
256+32y +y^2 = 400 + 144 + y^2
Y = 9
X = 15
Check
15^2 = 12^2 + 9^2
Proved
Using the Pythagorean’s theorem, we get
20^2 = 16^2 + 12^2
400 = 256 + 144
Likewise take the two triangles;
CBA & CMA
(16+y)^2 = 20^2 +x^2—-(1)
X^2 =12^2 + y^2——-(2)
So substitute the value of x^2 in (1)
256+32y +y^2 = 400 + 144 + y^2
Y = 9
X = 15
Check
15^2 = 12^2 + 9^2
Proved
Answered by
2
Answer:
In smaller triangle
H2=B2+P2
X2=144+y2..............1
In bigger triangle
(16+y)2=400+x2
X2=(16+y)2-400.............2
From 1&2
144+ y2 =(16+y) 2-400
144+y2=256+y2+32y-400
144+400-256=32y
544-256=32y
288=32y
9=y
So x2=144+81y
X2=255
X=15
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