Question

find x and y in the figure ​

Answer 1

Taking the triangle BCM
Using the Pythagorean’s theorem, we get
20^2 = 16^2 + 12^2
400 = 256 + 144
Likewise take the two triangles;
CBA & CMA

(16+y)^2 = 20^2 +x^2—-(1)

X^2 =12^2 + y^2——-(2)

So substitute the value of x^2 in (1)

256+32y +y^2 = 400 + 144 + y^2
Y = 9
X = 15

Check
15^2 = 12^2 + 9^2
Proved

Answer 2

Answer:

In smaller triangle

H2=B2+P2

X2=144+y2..............1

In bigger triangle

(16+y)2=400+x2

X2=(16+y)2-400.............2

From 1&2

144+ y2 =(16+y) 2-400

144+y2=256+y2+32y-400

144+400-256=32y

544-256=32y

288=32y

9=y

So x2=144+81y

X2=255

X=15