find x and Y in the following figure
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in triangle DCB
DC=DB
so angle Dbc=angle dcb (angles opposite to equal sides are equal.
angle cdb=180-96(linear pair)
=84
now in triangle dcb
angle dcb +angle Dbc +angle cdb=180 (angle sum property)
2 angle dcb+84=180 (angle dcb=dbc)
2 angle dcb=180-84
2 angle dcb=96
angle dcb=96
2
angle dcb=48
so y=48
now in triangle abc
angle abc+angle acb+ angle bac=180 (angel sum property)
90+48+x=180
138+x=180
x=180-138
x=42
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