Question

find x and y in the following figure

Answer 1

hey frnd....
in the given figure...
<BCD = <CBA (alternate angles)
and in ∆ ACE
AC = CE
so.. <CAE = <AEC = z°
so in ∆ ACE

<ACE + <CAE + <AEC = 180°
70° + z + z = 180°
2z = 180-70
z = 110/2
z = 55°

now in line CEB
y + z = 180
y = 180-55
y = 125°

Now in ∆ AEB
<EAB + <ABE + <AEB = 180°
20+125 + <ABE = 180
x = 180-145°
x = 35°

so the value of...
x = 35°
y = 125°

HOPE THIS HELP YOU ☺☺❤❤❤❤