find x and y in the following figures
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Before going forward, I'll name the point where all the lines meet (in the centre of the square) C
Since this is a square, we can assume that,
<S = 90
<R = 90
<Q = 90
<P = 90
The angle y° bisects the <S . So we can say that
<y = 1/2 <S
To be more clearly, <y = half of <S
= 90/2
= 45°
Now let us consider triangle PQR. First, we'll find all the angles one by one.
= <QPC = 90/2 = 45
= <PQC = 90/2 = 45
= <x° = 180 - 45 + 45 (Sum of the angles of a triangle is always 180)
= 180 - 90
= 90°
So, we just solved this question. The answers are:
<x = 90°
<y = 45°
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