find x and y in the following figures
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Solution: Since, ABCD is a rectangle.
Therefore, CDllAB
So,. Angle OCD=angle BAO
or,. (x+36)°=68°
or,. x=68°-36°
or,. x=32°
We know that diagonal of triangle bisect eact-other in equal length.
Therefore, AO=BO
Since, AO=BO
So, ∆AOB is an isosceles triangle.
Thus, Angle ABO=Angle BAO
=68°
Now,angle BAO+angleAOB+y°=180°
or,. 68°+68°+y°=180°
or,. y°=180°-136°
or,. y°=44°
Therefore, CDllAB
So,. Angle OCD=angle BAO
or,. (x+36)°=68°
or,. x=68°-36°
or,. x=32°
We know that diagonal of triangle bisect eact-other in equal length.
Therefore, AO=BO
Since, AO=BO
So, ∆AOB is an isosceles triangle.
Thus, Angle ABO=Angle BAO
=68°
Now,angle BAO+angleAOB+y°=180°
or,. 68°+68°+y°=180°
or,. y°=180°-136°
or,. y°=44°
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0
Answer:
y=44° and x=32°
Step-by-step explanation:
please refer the pic..
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