find x and y in the following figures WITH REASONS NO DIRECT ANSWER
Answers
Answer:
x = 45°
y = °
Step-by-step explanation:
Given:
PQ is bisected by point A
QR is bisected by point C
PQ = QR (all sides are equal in a square)
Then, PA = QC (common)
Thus, ∆AQC is an isosceles triangle
angle AQC = 90° (the interior angles of a square measure 90°)
Then, the other two angles are (QAC & QCA) are 45° each (angle sum prop. of a triangle & any two interior angles of an isosceles triangle are equal)
In the rectangle PQCB, angle QCB measures 90° (interior angles of a rectangle measure 90°)
Then, y° + 60° = 90°
=> y° = 90°- 60°
=> y° = 30° (ans 1)
In the rectangle PQCB:
QC = DB (opp. sides of a rectangle are equal)
angles ADB & CQA are 90° each (interior angles of a rectangle measure 90°)
DA = QA (given)
Then ∆ADB is congruent to ∆AQC (under SAS criteria)
Then, angle DBE = angle QCE (corresponding parts of congruent triangles)
x° = 45° (ans 2)p