Question

find x and y in the given figure ​

Answer 1

Answer:

in ∆ BOC

180° = 90+ 3y+ 6 +4y

180° = 90° +7y + 6 °

y = 12

in ∆ AOD

180 = 90 +2x -6

x = 42

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Answer 2

Answer:

In ΔAOD,

x - 6 + x + 90 = 180°        (ANGLE SUM PROPERTY)

2x + 84 = 180

2x = 180 - 84

2x = 96

x = 96/2

  = 48

In ΔCOB,

4y + 90 + 3y + 6 = 180°   (ANGLE SUM PROPERTY)

7y + 96 = 180°

7y = 180 - 96

    = 84

y = 84/7

  = 12

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