find x and y in the given figure
*please answer with solving*
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1
PQ is a mirror plane
MO is the normal
AM is the incident ray and MN is the reflected ray
Angle of incident is equal to angle of reflection.
angle QMN = angle PMA
PMA = 35°
x=35°
PQ is perpendicular to MO
PMO is 90°
x+y=90
y=90-35
y=55°
HOPE IT HELPS...
Answered by
3
angle of incidence is equal to angle of reflection
therefore x=35°
y =90°-35°=55°
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