find x and y in thevfollowing
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x =60 y=60..…………… ok
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quadrilateral DABC is a rhombus
given: angle OAB= 30°
diagonals of rhombus are perpendicular bisector of each other.
therefore, angle OAB=90°
now,
angleA + angleB + angleC = 180°
30° + x° + 90° = 180°
120° + x° = 180°
x° = 180° - 120°
x° = 60°
CBA= ADC (opposite angles of a rhombus are congruent)
therefore,half of CBA = half of ADC
OBA = ODA
but OBA= 60°...(angle B =x°=60°)
therefore, angle ODA= 60°...
i.e. y°= 60°
given: angle OAB= 30°
diagonals of rhombus are perpendicular bisector of each other.
therefore, angle OAB=90°
now,
angleA + angleB + angleC = 180°
30° + x° + 90° = 180°
120° + x° = 180°
x° = 180° - 120°
x° = 60°
CBA= ADC (opposite angles of a rhombus are congruent)
therefore,half of CBA = half of ADC
OBA = ODA
but OBA= 60°...(angle B =x°=60°)
therefore, angle ODA= 60°...
i.e. y°= 60°
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