Question

find x and y x-4y=0 and 2x-3y=14 by substitution method
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\huge\underline{\overline{\mid\star{\mathfrak{\pink{★Solution★}}\star\mid}}}$

Equations are—

• x - 4y = 0 -------(1)
• 2x - 3y = 14 -------(2)

Now,

2 × eqn(1) => 2x - 8y = 0 -------(3)

So,

eqn(2) - eqn(3)

=> 2x - 3y - (2x - 8y) = 14 -0

=> 2x - 3y - 2x + 8y = 14

=> 5y = 14

=> y = 14/5

• Putting the value of y in eqn(1) we get ,

x - 4 × (14/5) = 0

=> x - ( 56/5) = 0

=> x = 56/5

$\huge{\colorbox{yellow}{\underline{\underline{x\:=56/5\:\:and \:\:y\:=\:14/5}}}}$