find x
Angle c is 30
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Let point 'x' be angle DEC.
Here,
ABC+ACB+CAB=180°[Angle Sum Prprty
of triangle]
=>ABC+30°+34°=180°
=>ABC+64°=180°
=>ABC=180°-64°
=>ABC=116°
Now,
ABC+DBC=180°[Linear pair]
=> 116°+DBC=180°
=> DBC=180°-116°
=> DBC=64°
Again,
DEB+EBD+BDE=180°[Angle Sum Prprty
of triangle]
=>DEB+64°+45°=180°
=>DEB+109°=180°
=>DEB=180°-109°
=>DEB=71°
So,
DEB+DEC=180°[Linear pair]
=>71°+DEC=180°
=>DEC=180°-71°
=>DEC=109°
.·.x=109°
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