find x angle COF DOA BOE
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Here is your answer :
/_COF = /_EOD = 5x ( V.Opp. angles)
Now, BA is a straight line and sum of all angles on straight line = 180°
•°•/_BOC + /_COF + /_AOF = 180°
3x + 5x + 2x = 180°
10x = 180°
x = 180°÷10
x = 18°
So,
/_COF = 5x = 5*18 = 90°
/_DOA = 3x = 3*18 = 54°
/_BOE = 2x = 2*18 = 36°
/_COF = /_EOD = 5x ( V.Opp. angles)
Now, BA is a straight line and sum of all angles on straight line = 180°
•°•/_BOC + /_COF + /_AOF = 180°
3x + 5x + 2x = 180°
10x = 180°
x = 180°÷10
x = 18°
So,
/_COF = 5x = 5*18 = 90°
/_DOA = 3x = 3*18 = 54°
/_BOE = 2x = 2*18 = 36°
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