Question

Find X
answer should be 1/3
give explaination ​

Answer 1

Given,

$\sf \qquad \qquad \frac{3x - 2}{3} + \frac{2x + 3}{2} = x + \frac{7}{6}$

To find,

• The value of x

Solution,

$\sf \qquad \qquad \frac{3x - 2}{3} + \frac{2x + 3}{2} = x + \frac{7}{6}$

Now taking LCM of denominators

LCM is 6

$\sf \qquad \qquad \longmapsto \frac{2(3x - 2) + 3(2x + 3)}{6} = x - \frac{7}{6}$

$\sf \qquad \qquad \longmapsto \frac{6x - 4 + 6x + 9}{6} = \frac{6x + 7}{6}$

$\sf \qquad \qquad \longmapsto \frac{12x + }{6} = \frac{6x + 7}{6 }$

$\sf \qquad \qquad \longmapsto6(12x + 5) = 6(6x + 7)$

$\sf \qquad \qquad \longmapsto72x + 30 = 36x - 42$

$\sf \qquad \qquad \longmapsto72x - 36x = 42 - 30$

$\sf \qquad \qquad \longmapsto36x = 12$

$\sf \qquad \qquad \longmapsto \: x = \cancel \frac{12}{36}$

$\sf \qquad \qquad \red{ \boxed{ \longmapsto \boxed{ \frak{x = \frac{1}{3} }}} }$