find x
can someone answer
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Step-by-step explanation:
3×3^5x ÷ 9^2 = 1/27
(3^(1+5x))/3^4=1/3^3
3^(1+5x-4)×3^3= 1
(3^5x-3)×3^3= 1
3^5x-3+3= 1
3^5x= 1
(3^5)^x = 1
243^x= 1
taking log on both sides,
log243^x= log1
xlog243= o [since log 1=0]
x=0
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