Question

FIND X (chp-10 Circles Class 9 CBSE NCERT)
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Answer 1

Answer:

In triangle AOC

Angle AOC = 90°

AO = CO ( radius of the circle)

Angle OAC = Angle OCA

LET THE ANGLES BE X

ATQ

2X = 180° - 90°

2X = 90°

X= 45°

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