Question

find x cube minus y cube if x minus Y is equal to 5 and X Y is equal to 14​

Answer 1

Answer:

335

Step-by-step explanation:

According to the question,

x-y=5

xy=14

x^3-y^3=(x-y)^3+3xy(x-y)

=5^3+3*14*5

=125+210

=335

Answer 2

Step-by-step explanation:

The value of x^3-y^3 are -370 or 316

Step-by-step explanation:

Given Equations: x-y = 4x−y=4 --- 1

xy=21xy=21 ---2

Substitute the value of x from 2 in 1

x-y = 4x−y=4

\frac{21}{y}-y=4

y

21

−y=4

21-y^2=4y21−y

2

=4y

y^2-21+4y=0y

2

−21+4y=0

(y-3)(y+7)=0(y−3)(y+7)=0

y=3,-7y=3,−7

Substitute the value of x in 1

At y = 3

x-y = 4

x-3=4

x= -7

So, x^3-y^3=(-7)^3-3^3=-370x

3

−y

3

=(−7)

3

−3

3

=−370

At y=-7

x-(-7) = 4

x+7=4

x= 4-7

x= -3

So,x^3-y^3=(-3)^3-(-7)^3=316x

3

−y

3

=(−3)

3

−(−7)

3

=316

Hence the value of x^3-y^3 are -370 or 316

#Learn more:

If x is equal to 2 minus y then find the value of x cube + y cube minus 5

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