Question

Find ‘x’ for this question 4-7x=11/4

Answer 1

We have been asked to find 'x' in $\tt{ 4 - 7x = \dfrac{11}{4}}$

Firstly we will transpose the non 'x' term i.e 4 to the other side of the equal to sign.

$\longrightarrow{\tt{7x = \dfrac{11}{4} - 4}}$

$\longrightarrow{\tt{7x = \dfrac{11}{4} - \dfrac{4}{1}}}$

After taking LCM and also operating the numerator we get :

$\longrightarrow{\tt{7x = \dfrac{11-16}{4}}}$

$\longrightarrow{\tt{7x = \dfrac{-5}{4}}}$

$\longrightarrow{\tt{x = \dfrac{\dfrac{-5}{4}}{7}}}$

$\longrightarrow{\tt{ x = \dfrac{-5}{4 \times 7}}}$

$\large{\boxed{\tt{x = \dfrac{-5}{28}}}}$

Answer 2

Answer:

$\huge\bold\star\red{Answer}\star$

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Given:-

• linear equation 4-7x=11/4

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To find:-

• value of x for the equation

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Solution:-

Given,

$4 - 7x = \frac{11}{4}$

$= > ( - 7x) = \frac{11}{4} - 4$

$= > 7x = 4 - \frac{11}{4}$

$= > 7x = \frac{11 - 16}{4}$

$= > 7x = \frac{( - 5)}{4}$

$= > x = \frac{( - 5)}{28}$

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•°•required value of x is (-5)/28

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$\large\bf\green{Hope\:this\:help\:you}$