Question

find x for which
$sin x = {sin}^{ - 1} x$
​

Answer 1

Answer:

90°

Explanation:

$\sin(x) = { \sin}^{ - 1} x \\ \sin(x) \: = \frac{1}{ \sin(x) } \\ { \sin}^{2} x = 1 \\ \sin(x) = \sqrt{1} \\ \sin(x) = 1$

x=90°