Question

Find 'x' from the attached image. Would really appreciate ^o^

Answer 1

Answer:

Step-by-step explanation:

we know that sin A is 3/4

using the formula cos^2 A+ sin^2 A =1

we get cos A=√7/4

thus sec A = 4/√7, cosec A =4/3 and cot A =√7/3

substituting these values we get

{(16/9 - 7/9)/(16/7 - 1)}^1/2 + 2√7/3 = √7/x +√7/4

=>√(7/9) + 2√7/3=√7/x +√7/4

=> √7-√7/4=√7/x

ie x=4/3

another easier method :

[only if u know trigonometric identities]

cosec^2 a - cot^2 a =1 and sec^2 a -1= tan^2 a

thus the terms inside the root can be simplified to cot a

and then u can substitute the above given values and find x