Question

find x
(i) 2^2х - 2^x+3 +2^4 = 0​

Answer 1

Step-by-step explanation:

hey mate here is your answer

Answer 2

Answer:

$\red { Value \: of \: x } \green {= 2 }$

Step-by-step explanation:

$Given \:2^{2x} - 2^{x+3} + 2^{4} = 0$

$\implies (2^{x})^{2} - 2^{x} \times 2^{3} + 16 = 0$

$\implies (2^{x})^{2} - 8 \times 2^{x} + 16 = 0$

$\implies (2^{x})^{2} - 2 \times 2^{x} \times 4+ 4^{2} = 0$

$\implies ( 2^{x} - 4 )^{2} = 0$

$\boxed { \pink { a^{2} - 2ab + b^{2} = ( a-b)^{2} }}$

$\implies 2^{x} - 4 = 0$

$\implies 2^{x} = 4$

$\implies 2^{x} = 2^{2}$

$\implies x = 2$

$\boxed { \pink { Since, If \: a^{m} = a^{n} \implies m = n }}$

Therefore.,

$\red { Value \: of \: x } \green {= 2 }$

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