Question

Find x
(i) (-3x+1)/(x-2) = 3
(ii) (5x + 34)/3x = 49
(iii) 19x + 68 = 2x + 3
(iv) 5x + 9 = 19
(v) 9x + 11 = 5x - 3​

Answer 1

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

1. $\dfrac{-3x + 1}{x - 2} = 3$
2. $\dfrac{5x + 34}{3x} = 49$
3. 19x + 68 = 2x + 3
4. 5x + 9 = 19
5. 9x + 11 = 5x - 3

To find:

• Value of x

Solution:

$(i)\implies \dfrac{-3x+1}{x-2} = 3 \\ \\ \implies -3x+1 = 3(x-2) \\ \implies -3x+1 = 3x-6 \\ \implies 3x+3x = 1 + 6 \\ \implies 6x = 7 \\ \\ \implies x = \dfrac{7}{6}$

$(ii)\implies \dfrac{5x+34}{3x} = 49 \\ \\ \implies 5x+34= 49*3x \\ \implies 5x+34 = 147x \\ \implies 147x - 5x = 34 \\ \implies 142x = 34 \\ \\ \implies x = \dfrac{34}{142} \\ \\ \implies x = \dfrac{17}{71}$

$(iii) \implies 19x + 68 = 2x + 3 \\ \implies 19x - 2x = 3 - 68 \\ \implies 17x = -65 \\ \\ \implies x = \dfrac{-65}{17}$

$(iv) \implies 5x + 9 = 19 \\ \implies 5x = 19 - 9 \\ \implies 5x = 10 \\ \implies x = 2$

$(v) 9x + 11 = 5x - 3 \\ \implies 9x - 5x = -3 - 11 \\ \implies 4x = -14 \\ \\ \implies x = \dfrac{-14}{4} \\ \\ \implies x = \dfrac{-7}{2}$

Hope it helps!!!!

Answer 2

$\huge\underline{\overline{\mid{\bold{\blue{\mathcal{ANSWER}}\mid}}}}$

To Find:-

• The Value of X

Solution:-

$1) \: \: \: (-3x+1)/(x-2) = 3$

$= > - 3x + 1 = 3x - 6$

$= > - 3x - 3x = - 6 - 1$

$= > - 6x = - 7$

$= > x = \frac{ - 7}{ - 6}$

$= > x = \frac{7}{6}$

$2) \: \: \: \: (5x + 34)/3x = 49$

$= > 5x + 34 = 49 \times 3x$

$= > 5x + 34 = 147x$

$= > 5x - 147x = - 34$

$= > - 142x = - 34$

$= > x = \frac{ - 34}{ - 142}$

$= > x = 0.239$

$3) \: \: \: 19x + 68 = 2x + 3$

$= > 19x - 2x = - 68 + 3$

$= > 17x = - 65$

$= > x = 3.82$

$4) \: \: \: 5x + 9 = 19$

$= > 5x = 19 - 9$

$= > 5x = 10$

$= > x = \frac{10}{5}$

$= > x = 2$

$5) \: \: \: 9x + 11 = 5x - 3$

$= > 9x - 5x = - 11 - 3$

$= > 4x = - 14$

$= > x = \frac{ - 14}{4}$

$= > x = \frac{ - 7}{2}$