find x if (-1/3) raise to -18÷ (-1/3)raise to 7=(-1/3)raise to power -2x+1
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Question :-
Find x if \rm \dfrac{( \frac{ - 1}{3} ) ^{ - 18}}{( \frac{ - 1}{3} ) ^{ 7}} = (\dfrac{ - 1}{3})^{ - 2x + 1}
(
3
−1
) 7(3−1)−18=(3−1)−2x+1
.
Answer
➩ \rm \dfrac{\Big( \frac{ - 1}{3}\Big) ^{ - 18}}{\Big( \frac{ - 1}{3} ) ^{ 7}} = (\dfrac{ - 1}{3}\Big)^{ - 2x + 1}
(
3
−1
)
7
(
3
−1
)
−18
=(
3
−1
)
−2x+1
ㅤ
➩
3
−1
)
−18−7
=(
3
−1
)
−2x+1
ㅤ
➩ \r
3
−1 )−25 =(3−1)−2x+1
➩ -25 = -2x + 1−25=−2x+1
➩ 2x = 25 + 12x=25+1
➩ 2x = 262x=26
➩ x = 26/2
➩ x = 13
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