Question

find x if 1/x = ( 2^74+2^72)/(2^72+2^70) please help solving this​

Answer 1

Answer:

1/4

Step-by-step explanation:

1/x = ( 2^74+2^72)/(2^72+2^70)

1 = 2^72(2^2 + 1)

x 2^70(2^2 + 1)

1 = 2^2

x

x = 1/2^2

x = 1/4

Answer 2

Step-by-step explanation:

Given :-

1/x = ( 2^74+2^72)/(2^72+2^70)

To find :-

Find the value of x?

Solution:-

Method-1:-

Given that :

1/x = ( 2^74+2^72)/(2^72+2^70)

=> 1/x=[(2^70×2^4)+(2^70×2^2]/[(2^70×2^2)+2^70]

Since a^m×a^n = a^(m+n)

=>1/x = [2^70(2^4+2^2)]/[2^70(2^2+1)]

On cancelling 2^70

=> 1/x = (2^4+2^2)/(2^2+1)

=> 1/x = (16+4)/(4+1)

=> 1/x = 20/5

=> 1/x = 4

=>x = 1/4

Method -2:-

Given that :

1/x = ( 2^74+2^72)/(2^72+2^70)

=>x = (2^72+2^70)/ ( 2^74+2^72)

=>x=[(2^70×2^2)+2^70]/[(2^70×2^4)+(2^70×2^2]

Since a^m×a^n = a^(m+n)

=>x= [2^70(2^2+1)]/ [2^70(2^4+2^2)]

On cancelling 2^70

=> x = (2^2+1)/(2^4+2^2)

=>x = (4+1)/(16+4)

=>x = 5/20

=> x = 1/4

Answer:-

The value of x for the given problem is 1/4

Used formulae:-

• a^m×a^n = a^(m+n)

• a/b = 1/(b/a)