find x if (-2/3)^-13×(3/-2)^8=(-2/3)^-2x+1
nayakyashi:
the answer should be 11 given at the back of the book i am not getting the right answer
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I solved your problem
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Answers
Answered by
88
we have
(-2/3)^-13 × (3/-2)^8=(-2/3)^-2x+1
=》(-2/3)^-13 ×(-2/3)^-8=(-2/3)^-2x+1
when base are equal then power will also equal
=》-13 +(-8)=-2x+1
=》-13-8-1=-2x
=》-22=-2x
cancelling (-) from both sides
22=2x
=》22/2=x
=》11=x
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why are you asking this
do u know about the formula of a^2+b^2
hii
Answered by
10
Answer:11
Step-by-step explanation:
(−2/3)
−13
×(3/−2)
8
=(−2/3)
−2x+1
(−2/3)
−13
×(3/−2)
−8
=(−2/3)
−2x+1
(−2/3)
−13−8
=(−2/3)
−2x+1
(−2/3)
−21
=(−2/3)
−2x+1
Now by comparing the powers, we get
−21=2x+1
2x=1+21
2x=22
x=22/2
=11
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