Question

Find x if (−2/3 ) ^-13 x ( 3/−2 )^8 = (−2/3 )^-2x +1
pls answer it

Answer 1

Answer:

use identity to solve this question

Step-by-step explanation:

Answer 2

answer is

11

quuestion is

$\frac{-2}{3x }^{-13}*\frac{3}{-2}^{8}=\frac{-2}{3}^{-2x+1}$

step by step answer

Let us simplify the given expression,

$=\frac{-2}{3x }^{-13}*\frac{3}{-2}^{8}=\frac{-2}{3}^{-2x+1}$

$=\frac{-2}{3x }^{-13}*\frac{3}{-2}^{-8}=\frac{-2}{3}^{-2x+1}$

$=\frac{-2}{3x }^{-13-8}=\frac{-2}{3}^{-2x+1}$

Now by comparing the powers, we get

=−21=2x+1

=2x=1+21

=2x=22

=x=22/2

extra information

$\begin{gathered}\boxed{\begin{minipage}{5 cm}\bf{\dag}\:\:\underline{\text{Law of Exponents :}}\\\\\bigstar\:\:\sf\dfrac{a^m}{a^n} = a^{m - n}\\\\\bigstar\:\:\sf{(a^m)^n = a^{mn}}\\\\\bigstar\:\:\sf(a^m)(a^n) = a^{m + n}\\\\\bigstar\:\:\sf\dfrac{1}{a^n} = a^{-n}\\\\\bigstar\:\:\sf\sqrt[\sf n]{\sf a} = (a)^{\dfrac{1}{n}}\end{minipage}}\end{gathered}$