Question

find X if (2/5)^3*(2/5)^-6=(2/5)^2x-1​

Answer 1

Answer:

Step-by-step explanation:

Since bases are same,we will look only at the exponents.

Now a raised to b *a raised to c= raised to b+c

Therefore 2/5³ * 2/5 raised to -6

=2/5 raised to -3

Now as I said we will only look at the exponents,

-3=2x-1

-2=2x

Therefore, x=-1

Answer 2

$your \: question \: \\ = ({ \frac{2}{5} })^{3} \times ( \frac{2}{5}) ^{ - 6} = (\frac{2}{5} ) {}^{2x - 1}$
$answer =$
$( \frac{2}{5} ) {}^{3} \times ( \frac{2}{5} ) {}^{ - 6} =( \frac{2}{5} ) {}^{(3) + ( - 6)}$
$( \frac{2}{5} ) {}^{ - 3} = ( \frac{2}{5} ) {}^{2x - 1}$
on comparing;
$- 3 = 2x - 1 \\ - 3 + 1 = 2x \\ - 2 = 2x \\ \\ \frac{ - 2}{2} = x \\ - 1 = x$
so, the value of x is -1

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