find x if 2/9^5*9/2^-4=[(2/9)^3]^2x*(9/2)^-3
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(92)3×(92)6=(92)2m−1
⇒(92)3+6=(92)2m−1
Since bases are same, we can equate the powers,
⇒9=2m−1
⇒2m=10 or m=210=5
∴m=5
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Answer:
Fi ind x if (2/9) ^ 5 * (9/2) ^ - 4 = [(2/9) ^ 3] ^ (2x) * (9/2) ^ - 3 x if
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