find X if 2 log 5+1/4 log 81-log3=log X
Answers
Answered by
25
Answer:
25
Step-by-step explanation:
property
log(x^a)=alogx
81=3^4
(1/4)log81= (1/4)*4log3=log3
substituting the above result in the problem
2log5+log3-log3=2log5=log25
Answered by
33
The value of X is 25
We know that logx^m = mlogx
∴ 2log5 + 1/4log81 - log3 = logX
⇒ 2log5 + 1/4log3⁴ - log3 = logxX
⇒ log5² + 4/4log3 - log3 = logxX
⇒ log25 + log3 - log3 = logxX
⇒ log25 = logxX
⇒ X = 25
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