find x,if: 2+log x = log 45- log 2+log 16- 2 log 3
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Answer:
2/5
Step-by-step explanation:
Given,
2+log x=log45-log2+log 16-2 log3
=>2+log x=log(45/2)+log16-log(3²)
=>2+log x=log[(45/2)x16]-log9
=>2+log x=log360-log9
=>2+log x=log(360/9)
=>2+log x=log 40
=>log x=log40 - 2
=>log x=log40-log(10²)
=>log x=log40 - log100
=>log x=log(40/100)
=>log x=log(2/5)
Taking antilog on both sides, we get
=>x=2/5
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