find x if 21^√x+20^√x=29^√x
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Given : 21^√x+20^√x=29^√x
To Find: Solve for x :
Solution:
21^√x+20^√x=29^√x
Pythagorean triplet :
21² + 20² = 29²
Comparing both
√x = 2
Squaring both sides
=> x = 2²
=> x = 4
Value of x = 4
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