Question

Find x, if 25, x, x, 49 are in proportion.​

Answer 1

In th given question,

• 25:x::x:49
• 25:x::x:4925/x=x/49
• 25:x::x:4925/x=x/4925*49=X^2
• 25:x::x:4925/x=x/4925*49=X^21225=x^2
• 25:x::x:4925/x=x/4925*49=X^21225=x^2X=√1225
• 25:x::x:4925/x=x/4925*49=X^21225=x^2X=√1225x=35

So, the value of X is 35