find x if 2log5+½log9-log3=logx
Answers
Answered by
20
2log5 + ½log9 - log3 = logx
or, log5² + log9^½ - log3 = logx
or, log (25 ×3 ÷3) = logx [ since, log a + log b =log ab and log a - log b =log(a/b)]
or, log 25 = log x
So, x = 25 (ans)
or, log5² + log9^½ - log3 = logx
or, log (25 ×3 ÷3) = logx [ since, log a + log b =log ab and log a - log b =log(a/b)]
or, log 25 = log x
So, x = 25 (ans)
Answered by
0
Answer:
x=25
Step-by-step explanation:
2log5+
2
1
log9−log3
⇒log25+log3−log3
log25=logx
x=25
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