Find x if (2x/x-5)^2 + 5 (2x/x-5)-24=0
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Answered by
69
let 2x/x-5 be a
a^2 + 5a - 24 =0
a^2 +8a -3a -24
a(a+8) - 3(a+8)
(a+8)(a-3)
now put value of a
2x/x-5 - 3 =0
2x/x-5 = 3
2x=3x-15
x=15
in second case
2x/x-5 +8 =0
2x / x-5=-8
2x = -8x +40
10 x =40
x=4
so value of can be 4 and 15 both will satisfy the equation
a^2 + 5a - 24 =0
a^2 +8a -3a -24
a(a+8) - 3(a+8)
(a+8)(a-3)
now put value of a
2x/x-5 - 3 =0
2x/x-5 = 3
2x=3x-15
x=15
in second case
2x/x-5 +8 =0
2x / x-5=-8
2x = -8x +40
10 x =40
x=4
so value of can be 4 and 15 both will satisfy the equation
Answered by
57
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