Question

Find x if 3x^2 +4x +4, 2x^2 +3x +3 and 3x + 8 are the term of A.P, where x is a natural number​. Please answer fast. Will mark as Brainliest..

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

d= a2-a1

d=2x^2+3x+3 -(3x^2+4x+4)

d=-x^2 -x-1

also,

d=a3-a2

d=3x-8-(2x^2+3x+3)

d=-2x^2-11

equating values of d

2x^2 -11=-x^2-x-1

3x^2+x-10=0

3x^2+6x-5x-10

3x(x+2)+5(x+2)

(3x+5)(x+2)

therefore x=-5/3 or -2