find x if 4,6,8,x are in proportion
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Answered by
1
Step-by-step explanation:
ANSWER
Given the relation the relation R be defined on A as follows R={(a,a),(b,c),(a,b)}.
Now, to make this relation R to be reflexive we are to add the elements like (x,x) for all x∈A.
The the relation will be R={(a,a),(b,b),(c,c),(b,c),(a,b)}.
Now this relation is reflexive but not transitive as (a,b)∈A,(b,c)∈A⇒(a,c)
∈A.
Now to make this relation to be transitive we are to add (a,c).
Then the relation will be R={(a,a),(b,b),(c,c),(b,c),(a,b),(a,c)}
Answered by
2
Answer:
Here is the answer:
Step-by-step explanation:
If 4,6,8,x are in proportion then x-8=8-6=6-4
So from here the common difference is 2
And x-8=2
x=8+2
x=10.
So the value of x is 10 and it is in proportion too.
HOPE IT HELPS.
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