Find 'x' if (4/9)^4 × (4/9)^7 = (4/9)^2x-1 ?
Answers
Answered by
6
(4/9)^4×(4/9)^7=(4/9)^2x-1
On L.H.S. same base we will add the power
(4/9)^4+7=(4/9)^2x-1
On both side there is same base so, we can easily compare the power
11=2x-1
11+1=2x
12=2x
12/2=x
6=x
On L.H.S. same base we will add the power
(4/9)^4+7=(4/9)^2x-1
On both side there is same base so, we can easily compare the power
11=2x-1
11+1=2x
12=2x
12/2=x
6=x
Answered by
2
IF BASES ARE SAME THEN THE POWERS ARE ALSO SAME
SO ,
4+(-7) = 2x-1
4-7 = 2x-1
(-3) = 2x-1
2x = (-1)-(-3)
= (-1)+3
=(-2)
∴ x = (-2/2)
= (-1)
SO VALUE OF X IS (-1)
HOPE IT HELPS YOU
THANKYOU
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