Question

find x if (√6)^x+2=1​

Answer 1

$(\sqrt{6})^{x-2}=1$

$6^{x-2}=1$ ................(i)

Anything power 0 is 1,

$6^{0} =1$ ................(ii)

Comparing (i) and (ii)

$x-2=0$

$x=2$

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Answer 2

Answer:

-2

Step-by-step explanation:

(√6)^x+2 = 1

when 0 is raised to any number it becomes 1,

(√6)^x+2 = (√6)^0

Since bases are same,

x+2 = 0

x = -2