Find x, if 9 × 3^x = (27)^2x-3
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Hi ,
birthday boy
9 × 3^x = ( 27 ) ^ 2x -3
9 × 3^x = ( 3 ) ^3(2x-3)
3² × 3^x = ( 3 )^ 6x - 9
3^(2+x)= 3^(6x-9)
since a^m × a ^n = a^(m+n)
we know that,
if a^m = a^n then m= n
2+x = 6x-9
x-6x = -9-2
-5x = -11
x = (-11)/(-5)
therefore,
x = 11/5
I hope this helps you.
:)
birthday boy
9 × 3^x = ( 27 ) ^ 2x -3
9 × 3^x = ( 3 ) ^3(2x-3)
3² × 3^x = ( 3 )^ 6x - 9
3^(2+x)= 3^(6x-9)
since a^m × a ^n = a^(m+n)
we know that,
if a^m = a^n then m= n
2+x = 6x-9
x-6x = -9-2
-5x = -11
x = (-11)/(-5)
therefore,
x = 11/5
I hope this helps you.
:)
mysticd:
:)
Answered by
130
hope its help you............
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