Find x, if 9*3^x=(27)^2x-3
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Heya!!
9 × 3^x = 27^2x-3
=) 3^2 × 3^x = {(3^3)^2x-3}
=) 3^2+x = 3^6x-9
=) 2 + x = 6x - 9
=) x - 6x = -9 - 2
=) - 5x = - 11
=) x = -11/-5
=) x = 11/5
Hence, the val of x is 11/5.
Hope it helps uh.
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