Question

Find x, if 9,x,14,18,x,x,8, 10 and 4 have a mean of 11
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Answer 1

Answer:

Value of X is 12.

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Answer 2

Answer:

Given, class intervals are 1.1−2.0,2.1−3.0,3.1−4.0

Since, the intervals are represented in decimal, we add and subtract 0.05 to get the actual limits.

For class interval 1.1−2.0,

Class mark is

2

1.1+2.0

=

2

3.1

=1.55

Actual upper limit is 2.0+0.05=2.05 and

actual lower limit is 1.1−0.05=1.05

Similarly for 2.1−3.0,

Class mark is

2

2.1+3.0

=2.55

Actual upper limit is 3.0+0.05=3.05 and

actual lower limit is 2.1−0.05=2.05

Similarly for 3.1−4.0,

Class mark is

2

3.1+4.0

=3.55

Actual upper limit is 4.0+0.05=4.05 and

actual lower limit is 3.1−0.05=3.05

Therefore, actual upper limits are 2.05,3.05,4.05

Actual lower limits are 1.05,2.05,3.05

Class marks are 1.55,2.55,3.55

Step-by-step explanation:

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