find x, if angles of measures (x+ 10)° and (x-30)° are: (a) complementary to each other (b) supplementary to each other
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let complementary angles =90
then,
( x+10°) +(x-30°) = 90°
x+10+x-30=90
2x-20=90
2x=90+20
2x= 110
x=110÷2
x=55
now,
x+10= 55+10=65
x-30= 55-30=25
let supplementary angles =180
then,
x+10+x-30 =180
2x -20 = 180
2x= 180+20
2x=200
x=200÷2
x=100
now,
x+10=100+10 = 110
x-30=100-30 = 70
then,
( x+10°) +(x-30°) = 90°
x+10+x-30=90
2x-20=90
2x=90+20
2x= 110
x=110÷2
x=55
now,
x+10= 55+10=65
x-30= 55-30=25
let supplementary angles =180
then,
x+10+x-30 =180
2x -20 = 180
2x= 180+20
2x=200
x=200÷2
x=100
now,
x+10=100+10 = 110
x-30=100-30 = 70
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