Question

find x if cube root under 4 to the power 2 X + 1 by 2 is equal to cube root under 8 to the power 5


Pls answer fast​

Answer 1

Answer: 7/2

Solution:

$( { \sqrt[3]{4} })^{ 2x + \frac{1}{2} } = ({ \sqrt[3]{8} })^{5} \\ \\ = > {2}^{( \frac{2}{3} )( \frac{4x + 1}{2} )} = ( {2})^{5}$

Base same, powers equal:

4x + 1 = 5(3)

=> 4x = 14

=> x = 7/2

Answer 2

Answer:

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