Question

Find x if distance betweenp(x,-8) and q(-7,-3) is 13 units

Answer 1

Step-by-step explanation:

√(-7-x)^2+(-3+8)^2=13

square on both side

(-7-x)^2+(-3+8)^2=169

49+x^2+14x+25-169=0

X^2+14x-95=0

(x+19)(x-5)=0

x= -19 (or) 5