Question

find x ,if E is the centre of the circle

Answer 1

In the given fig. above

ED=EB (radii of circle)
So,
<EDB=<EBD [both 30°]

In triangle EBD
<EBD+<EDB+<BED=180° (triangle sum property)
30°+30°+<BED=180°
60°+<BED=180°
<BED=180°-60°
<BED=120°

we know that,
1/2<BED=<BAD
1/2×120°=<BAD
60°=<BAD

ABCD is a cyclic quadrilateral,

<A+<C=180° [sum of opposite angles of cyclic quadrilateral]

60°+x=180°
x=180°-60°
x=120°

۰۪۫H۪۫۰۰۪۫O۪۫۰۰۪۫P۪۫۰۰۪۫E۪۫۰ ۰۪۫I۪۫۰۰۪۫T۪۫۰ ۰۪۫H۪۫۰۰۪۫E۪۫۰۰۪۫L۪۫۰۰۪۫P۪۫۰۰۪۫S۪۫۰ ۰۪۫Y۪۫۰۰۪۫O۪۫۰۰۪۫U۪۫۰