Question

Find x if log (8x-3) to the base x -log4to the base x =2

Answer 1

$log_{x}(8x - 3) - log_{x}(4) = 2$
$= > log_{x}( \frac{8x - 3}{4} ) = 2$
$= > {x}^{2} = \frac{8x - 3}{4}$
$= > 4{x}^{2} = 8x - 3$
$= > 4 {x}^{2} - 8x + 3 = 0$
$= > 4 {x}^{2} - 6x - 2x + 3 = 0$
$= > 2x(2x - 3) - 1(2x - 3) = 0$
$= > (2x - 3)(2x - 1) = 0$
$= > x = \frac{3}{2} \: or \: \frac{1}{2}$
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Answer 2

Answer:

Same answer of artyaastha