find x if log k x.log5k = 3
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Use log(A,B) = 1/log(B,A)
log (k,x) * log(5,k) = 3
log (k,x) / log(k,5) = 3
log(k, x) = 3 log(k, 5)
log(k, x) = log(k, 5^3)
x = 5^3 = 125
YOU COULD HAVE also used log(A,B) / log(A,C) = lob(C, B)
log (k,x) / log(k,5) = 3
log(5, x) = 3
x = 5^3 = 125
Now that I think of it
YOU COULD HAVE also used log(A,B) × log(B,C) = lob(A, C)
log (k,x) × log(5,k) = 3
log(5,k) × log (k,x) = 3
log(5, x) = 3
x = 5^3 = 125
log (k,x) * log(5,k) = 3
log (k,x) / log(k,5) = 3
log(k, x) = 3 log(k, 5)
log(k, x) = log(k, 5^3)
x = 5^3 = 125
YOU COULD HAVE also used log(A,B) / log(A,C) = lob(C, B)
log (k,x) / log(k,5) = 3
log(5, x) = 3
x = 5^3 = 125
Now that I think of it
YOU COULD HAVE also used log(A,B) × log(B,C) = lob(A, C)
log (k,x) × log(5,k) = 3
log(5,k) × log (k,x) = 3
log(5, x) = 3
x = 5^3 = 125
shubu2727:
i hope it helps u
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